A capacitor of capacity 2µF is charged to a potential difference of 12V. It is then connected across an inductor of inductance 0.6mH. The current in the circuit at a time when the potential difference across the capacitor is 6.0 volt is ……× 10 –1 Amp.
Text Solution
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Sol. In case of oscillatory discharge of capacitor through an inductor
q = q 0 cos ωt with ω = 
q = CV
cos ωt = 
ωt = 
rad
ω = 
= 
rad/sec
I = 
= –q 0 ω sin ωt
| I | = CV 0 ω sin ωt
= 2 × 10 –6 × 12 × 
= 0.6 Amp
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